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A067864
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Numbers k such that k divides the sum of digits of 6^k.
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7
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OFFSET
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1,2
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COMMENTS
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Conjecture: the sequence is finite, since (sum of the digits of 6^k)/k -> log_10(6)*4.5 ~ 3.50168 as k->infinity (this is also a conjecture). - Robert Gerbicz, May 08 2008
Next term, if it exists, exceeds 100000. - Sean A. Irvine, Apr 05 2010
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LINKS
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EXAMPLE
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a(1)=3, so 3 divides the sum of digits of 6^3 (i.e., 2 + 1 + 6 = 9).
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CROSSREFS
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KEYWORD
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hard,nonn,base
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AUTHOR
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STATUS
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approved
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