1852 United States presidential election in Alabama
Appearance
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County Results
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Elections in Alabama |
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Government |
The 1852 United States presidential election in Alabama took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.
Alabama voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Alabama by a margin of 26.77%.
Results
[edit]1852 United States presidential election in Alabama[1][2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 26,881 | 60.89% | 9 | 100.00% | ||
Whig | Winfield Scott of New Jersey | William A. Graham of North Carolina | 15,061 | 34.12% | 0 | 0.00% | ||
Southern Rights | George Troup | N/A | 2,205 | 5.01% | 0 | 0.00% | ||
Total | 44,147 | 100.00% | 9 | 100.00% |
See also
[edit]References
[edit]- ^ "1852 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved December 2, 2017.
- ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 2, 2017.