1888 Georgia gubernatorial election
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Elections in Georgia |
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The 1888 Georgia gubernatorial election was held on 3 October 1888 in order to elect the Governor of Georgia. Democratic nominee and incumbent Governor John B. Gordon ran unopposed and thus won re-election.[1]
General election
[edit]On election day, 3 October 1888, Democratic nominee John B. Gordon won re-election with 100.00% of the vote, thereby holding Democratic control over the office of Governor. Gordon was sworn in for his second term on 30 November 1888.[2]
Results
[edit]Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic | John B. Gordon (incumbent) | 121,999 | 100.00 | |
Total votes | 121,999 | 100.00 | ||
Democratic hold |
References
[edit]- ^ "Gov. John Brown Gordon". National Governors Association. Retrieved 4 January 2024.
- ^ "GA Governor". ourcampaigns.com. 1 September 2005. Retrieved 4 January 2024.
Categories:
- Georgia (U.S. state) gubernatorial elections
- 1888 United States gubernatorial elections
- 1888 Georgia (U.S. state) elections
- October 1888 events
- Single-candidate elections
- 1888 in Georgia (U.S. state)
- 1880s in Georgia (U.S. state)
- 1880s Georgia (U.S. state) elections
- 1888 elections
- 1888 elections in North America
- 1888 elections in the United States
- United States gubernatorial elections in the 1880s
- Government of Georgia (U.S. state)