%I #7 Apr 18 2023 08:33:27

%S 2,2,16,134217728,

%T 115792089237316195423570985008687907853269984665640564039457584007913129639936

%N a(n) = 2^(n^n).

%F 2^(n^n) = 2^A000312(n) = A000079(A000312(n)). - _Jonathan Vos Post_, Dec 07 2004

%e 2^(2^2) = 16.

%Y Cf. A000079, A000312.

%K nonn

%O 0,1

%A _Parthasarathy Nambi_, Dec 06 2004