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A117707
Largest number of previous terms having at least one common digit in decimal representation.
1
0, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20, 20, 20, 20, 20, 21, 21, 22, 22
OFFSET
0,4
COMMENTS
a(n) = A003056(n) for n <= 63.
EXAMPLE
n=64: occurrences of digit d in the first 63 terms:
d=0:#{a(0),a(55),a(56),a(57),a(58),a(59),a(60),a(61),a(62),a(63)}=10,
d=1:#{a(1),a(2),a(55),a(56),a(57),a(58),a(59),a(60),a(61),a(62),a(63)}=11,
d=2:#{a(3),a(4),a(5)}=3,
d=3:#{a(6),a(7),a(8),a(9)}=4,
d=4:#{a(10),a(11),a(12),a(13),a(14)}=5,
d=5:#{a(15),a(16),a(17),a(18),a(19),a(20)}=6,
d=6:#{a(21),a(22),a(23),a(24),a(25),a(26),a(27)}=7,
d=7:#{a(28),a(29),a(30),a(31),a(32),a(33),a(34),a(35)}=8,
d=8:#{a(36),a(37),a(38),a(39),a(40),a(41),a(42),a(43),a(44)}=9,
d=9:#{a(45),a(46),a(47),a(48),a(49),a(50),a(51),a(52),a(53),a(54)}=10,
therefore a(64) = max{10, 11, 3, 4, 5, 6, 7, 8, 9, 10} = 11.
CROSSREFS
Sequence in context: A169894 A357930 A003056 * A163352 A087834 A172263
KEYWORD
nonn,base
AUTHOR
Reinhard Zumkeller, Apr 13 2006
STATUS
approved