%I #6 Sep 12 2015 12:43:41

%S 20,136,812,4752,27716,161560,941660,5488416,31988852,186444712,

%T 1086679436,6333631920,36915112100,215157040696,1254027132092,

%U 7309005751872,42600007379156,248291038523080,1447146223759340,8434586304032976,49160371600438532

%N The first of nine consecutive positive integers the sum of the squares of which is equal to the sum of the squares of eight consecutive positive integers.

%C For the first of the corresponding eight consecutive positive integers, see A262139.

%H Colin Barker, <a href="/A262140/b262140.txt">Table of n, a(n) for n = 1..1000</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (7,-7,1).

%F a(n) = 4*A076708(n+1).

%F a(n) = 7*a(n-1)-7*a(n-2)+a(n-3) for n>3.

%F G.f.: 4*x*(x-5) / ((x-1)*(x^2-6*x+1)).

%e 20 is in the sequence because 20^2 + ... + 28^2 = 5244 = 22^2 + ... + 29^2.

%o (PARI) Vec(4*x*(x-5)/((x-1)*(x^2-6*x+1)) + O(x^40))

%Y Cf. A076708, A262139.

%K nonn,easy

%O 1,1

%A _Colin Barker_, Sep 12 2015