editing
approved
a(n) = (-2)^n + (n+1)!/2 - (3+n)*Gamma(1+n,-2)/(2 *e^2). - Benedict W. J. Irwin, Jul 06 2020
reviewed
proposed
a(n) = (-2)^n + (n+1)!/2 - (3+n)*Gamma(1+n,-2)/(2 Ee^2). - Benedict W. J. Irwin, Jul 06 2020
a(n) = (-2)^n + (n+1)!/2 - ( - (3+n)*Gamma(1+n,-2)/(2 E^2). - Benedict W. J. Irwin, Jul 06 2020
a(n) = (-2)^n + (n+1)!/2 - (3+n)*Gamma(1+n,-2)/(2 E^2). - Benedict W. J. Irwin, Jul 06 2020
Benedict W. J. Irwin: Obtained from Inverse Z-transform of G(1/x)