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#28 by Peter Luschny at Tue Aug 09 02:29:26 EDT 2022
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#27 by Michel Marcus at Tue Aug 09 01:38:00 EDT 2022
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#26 by Michel Marcus at Tue Aug 09 01:37:58 EDT 2022
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#25 by Jon E. Schoenfield at Tue Aug 09 00:27:56 EDT 2022
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#24 by Jon E. Schoenfield at Tue Aug 09 00:27:46 EDT 2022
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| FORMULA
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a(n) = (n+3)!*binomial(n+6, 6)/3!; e.g.f.: (1+ + 18*x+ + 45*x^2+ + 20*x^3)/(1-x)^10.
If we define f(n,i,x)= sum(sum() = Sum_{k=1..n} Sum_{j=1..k} binomial(k,j)*stirling1Stirling1(n,k)*stirling2Stirling2(j,i)*x^(k-j),j=i..k),k=i..n) ), then a(n-3)=(-) = (-1)^(n-1)*f(n,3,-7), (n>=3). [_). - _Milan Janjic_, Mar 01 2009]
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| PROG
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(MAGMAMagma) [Factorial(n+3)*Binomial(n+6, 6)/6: n in [0..20]]; // G. C. Greubel, May 12 2018
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| STATUS
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approved
editing
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#23 by Alois P. Heinz at Fri Mar 20 09:24:53 EDT 2020
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#22 by F. Chapoton at Fri Mar 20 09:03:57 EDT 2020
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#21 by F. Chapoton at Fri Mar 20 09:03:46 EDT 2020
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| PROG
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(Sage) [binomial(n, 6)*factorial ((n-3)/factorial ((3) for n in range(6, 22)] # Zerinvary Lajos, Jul 07 2009
.... return f(n)/f(r)/f(n-r)
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| STATUS
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approved
editing
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Discussion
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| Fri Mar 20
| 09:03
| F. Chapoton: use space to indent python code
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#20 by N. J. A. Sloane at Sat Dec 07 12:18:22 EST 2019
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| PROG
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(Sage) [binomial(n, 6)*factorial (n-3)/factorial (3) for n in xrangerange(6, 22)] # Zerinvary Lajos, Jul 07 2009
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Discussion
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| Sat Dec 07
| 12:18
| OEIS Server: https://oeis.org/edit/global/2837
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#19 by Alois P. Heinz at Sat May 12 17:24:37 EDT 2018
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