Revision History for A161561
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#9 by Harvey P. Dale at Sat Oct 24 12:21:46 EDT 2020
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#8 by Harvey P. Dale at Sat Oct 24 12:21:43 EDT 2020
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| MATHEMATICA
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dsn[n_]:=Module[{k=n+1}, While[Total[IntegerDigits[k]]!=n, k++]; k]; Array[ dsn, 50] (* Harvey P. Dale, Oct 24 2020 *)
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| STATUS
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approved
editing
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#7 by Joerg Arndt at Sun Jun 08 10:02:46 EDT 2014
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#6 by Michel Marcus at Sun Jun 08 09:21:56 EDT 2014
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#5 by Michel Marcus at Sun Jun 08 09:21:51 EDT 2014
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| EXAMPLE
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a(4)=13 because the sums of digits of the candidates 5 to 12 are all different from n=4, and 13 is the first candidate with sum 1+3 = n = 4,.
and 13 is the first candidate with sum 1+3 = n = 4.
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| PROG
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(PARI) a(n) = my(m = n+1); while(sumdigits(m) != n, m++); m; \\ Michel Marcus, Jun 08 2014
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| STATUS
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approved
editing
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#4 by Russ Cox at Sat Mar 31 10:32:42 EDT 2012
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| AUTHOR
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_Enoch Haga (Enokh(AT)comcast.net), _, Jun 13 2009
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Discussion
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| Sat Mar 31
| 10:32
| OEIS Server: https://oeis.org/edit/global/789
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#3 by Russ Cox at Fri Mar 30 17:40:00 EDT 2012
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| EXTENSIONS
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More precise definition from _R. J. Mathar (mathar(AT)strw.leidenuniv.nl), _, Aug 30 2010
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Discussion
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| Fri Mar 30
| 17:40
| OEIS Server: https://oeis.org/edit/global/190
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#2 by N. J. A. Sloane at Sun Sep 12 03:00:00 EDT 2010
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| NAME
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NextThe smallest number highestlarger sumthan ofn thewith digitsdigital ofsum theequal naturalto numbersn.
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| COMMENTS
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If you add the digits of these terms you will have the sequence of the
natural numbers. For example, the sum of digits of 4 is 4, but the next
highest is 13, 1+3=4.
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| FORMULA
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a(4)=13 because 1+3=4. By "next highest" is meant the next term greater than
the number itself, 4 in this case.
a(n) = min{k>n: A007953(k) = n}.
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| EXAMPLE
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For a(1) through a(5), 10, 11, 12, 13, 14 translate to 1 2 3 4 5 (1+4=5)
a(4)=13 because the sums of digits of the candidates 5 to 12 are all different from n=4,
and 13 is the first candidate with sum 1+3 = n = 4.
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| CROSSREFS
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Cf. A161551 , A075360 , A054750.
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| KEYWORD
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base,easy,nonn,uned,new
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| EXTENSIONS
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More precise definition from R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Aug 30 2010
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#1 by N. J. A. Sloane at Tue Jun 01 03:00:00 EDT 2010
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| NAME
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Next highest sum of the digits of the natural numbers
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| DATA
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10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 29, 39, 49, 59, 69, 79, 89, 99, 199, 299, 399, 499, 599, 699, 799, 899, 999, 1999, 2999, 3999, 4999, 5999, 6999, 7999, 8999, 9999, 19999, 29999, 39999, 49999, 59999, 69999, 79999, 89999, 99999, 199999, 299999, 399999
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| OFFSET
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1,1
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| COMMENTS
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If you add the digits of these terms you will have the sequence of the
natural numbers. For example, the sum of digits of 4 is 4, but the next
highest is 13, 1+3=4.
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| FORMULA
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a(4)=13 because 1+3=4. By "next highest" is meant the next term greater than
the number itself, 4 in this case.
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| EXAMPLE
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For a(1) through a(5), 10, 11, 12, 13, 14 translate to 1 2 3 4 5 (1+4=5)
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| CROSSREFS
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A161551 A075360 A054750
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| KEYWORD
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base,easy,nonn,uned
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| AUTHOR
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Enoch Haga (Enokh(AT)comcast.net), Jun 13 2009
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| STATUS
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approved
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