Revision History for A239098
(Underlined text is an addition;
strikethrough text is a deletion.)
Showing all changes.
|
| |
| |
| |
|
|
#5 by N. J. A. Sloane at Sun Mar 23 19:53:35 EDT 2014
| |
| |
| |
|
|
#4 by N. J. A. Sloane at Sun Mar 23 19:53:32 EDT 2014
|
|
| COMMENTS
|
If the first column is omitted we get A075856, which has much more information about this triangle.
|
|
| REFERENCES
|
P. W. Shor, Problem 78-6: A combinatorial identity, in Problems and Solutions column, SIAM Review; problem in 20, p. 394 (1978); solution in 21, pp. 258-260 (1979).
|
|
| MAPLE
|
T:=proc(m, n) option remember;
if (m=0) and (n=0) then 1;
elif (m=0) or (n=0) then 0;
else (m-1)*T(m-1, n)+(m-1+n)*T(m-1, n-1); fi; end;
M:=20;
for m from 0 to M do
lprint([seq(T(m, n), n=0..m)]); od:
|
|
| CROSSREFS
|
Cf. A075856.
|
|
| STATUS
|
approved
editing
|
| |
| |
|
|
#3 by N. J. A. Sloane at Sun Mar 23 19:50:29 EDT 2014
| |
| |
| |
|
|
#2 by N. J. A. Sloane at Sun Mar 23 19:50:24 EDT 2014
|
|
| NAME
|
allocated for N. J. A. Sloane
Triangle read by rows: T(0,0)=1; T(m,0)=0; otherwise T(m,n) = (m-1)*T(m-1,n)+(m-1+n)*T(m-1,n-1).
|
|
| DATA
|
1, 0, 1, 0, 1, 3, 0, 2, 10, 15, 0, 6, 40, 105, 105, 0, 24, 196, 700, 1260, 945, 0, 120, 1148, 5068, 12600, 17325, 10395, 0, 720, 7848, 40740, 126280, 242550, 270270, 135135, 0, 5040, 61416, 363660, 1332100, 3213210, 5045040, 4729725, 2027025, 0, 40320, 541728, 3584856, 15020720, 43022980, 85345260, 113513400, 91891800, 34459425
|
|
| OFFSET
|
0,6
|
|
| EXAMPLE
|
Triangle begins:
1,
0, 1,
0, 1, 3,
0, 2, 10, 15,
0, 6, 40, 105, 105,
0, 24, 196, 700, 1260, 945,
0, 120, 1148, 5068, 12600, 17325, 10395,
0, 720, 7848, 40740, 126280, 242550, 270270, 135135,
...
|
|
| KEYWORD
|
allocated
nonn,tabl
|
|
| AUTHOR
|
N. J. A. Sloane, Mar 23 2014
|
|
| STATUS
|
approved
editing
|
| |
| |
|
|
#1 by N. J. A. Sloane at Mon Mar 10 11:32:17 EDT 2014
|
|
| NAME
|
allocated for N. J. A. Sloane
|
|
| KEYWORD
|
allocated
|
|
| STATUS
|
approved
|
| |
| |
|
|
