proposed
approved
editing
(Python)
from math import isqrt
def A319086(n): return ((-((s:=isqrt(n))*(s+1))**3*(2*s+1)>>1) + sum(k**2*(q:=n//k)*(q+1)*(2*k*(2*q+1)+3*q*(q+1)) for k in range(1, s+1)))//12 # Chai Wah Wu, Oct 21 2023
reviewed
def A319086(n): return sum((k*(m:=n//k)*(m+1)>>1)**2 for k in range(1, n+1)) # Chai Wah Wu, Oct 20 2023
Michel Marcus: sure