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Revision History for A319282

(Underlined text is an addition; strikethrough text is a deletion.)

Showing entries 1-10 | older changes
A319282 Numbers of the form 16^i*(16*j + 15).
(history; published version)
#12 by Susanna Cuyler at Mon Sep 17 15:44:41 EDT 2018
STATUS

proposed

approved

#11 by Jianing Song at Mon Sep 17 01:11:47 EDT 2018
STATUS

editing

proposed

#10 by Jianing Song at Mon Sep 17 01:09:02 EDT 2018
LINKS

Jianing Song, <a href="/A319282/b319282.txt">Table of n, a(n) for n = 1..9999</a> (all terms <= 150000)

STATUS

proposed

editing

#9 by Michel Marcus at Sun Sep 16 23:38:31 EDT 2018
STATUS

editing

proposed

#8 by Michel Marcus at Sun Sep 16 23:38:24 EDT 2018
CROSSREFS

Fourth powers: positvepositive: A319281; negative: this sequence (negated).

STATUS

approved

editing

Discussion
Sun Sep 16 23:38
Michel Marcus: typo
#7 by Peter Luschny at Sun Sep 16 17:12:43 EDT 2018
STATUS

proposed

approved

#6 by Jianing Song at Sun Sep 16 12:29:44 EDT 2018
STATUS

editing

proposed

#5 by Jianing Song at Sun Sep 16 12:28:29 EDT 2018
DATA

15, 31, 47, 63, 79, 95, 111, 127, 143, 159, 175, 191, 207, 223, 239, 240, 241, 255, 271, 287, 303, 319, 335, 351, 367, 383, 399, 415, 431, 447, 463, 479, 495, 496, 511, 527, 543, 559, 575, 591, 607, 623, 639, 655, 671, 687, 703, 719, 735, 751, 752, 767, 783, 799, 815

FORMULA

a(n) = 15*n + O(log(n)).

PROG

(PARI) isA319282(n)= n\16^valuation(n, 16)%16==15

CROSSREFS

A125169 is a proper subsequence.

#4 by Jianing Song at Sun Sep 16 10:05:42 EDT 2018
COMMENTS

{-a(n)} aregives all negative fourth powers modulo all powers of 2, that is, negative fourth powers over 2-adic integers.

#3 by Jianing Song at Sun Sep 16 08:07:19 EDT 2018
CROSSREFS

Perfect powers over 2-adic integers:

Squares: positive: A234000; negative: A004215 (negated);

Cubes: A191257;

Fourth powers: positve: A319281; negative: this sequence (negated).

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Last modified August 7 03:39 EDT 2024. Contains 375008 sequences. (Running on oeis4.)