Svoboda | Graniru | BBC Russia | Golosameriki | Facebook
login
The OEIS is supported by the many generous donors to the OEIS Foundation.

 

Logo
Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)

Revision History for A322582

(Underlined text is an addition; strikethrough text is a deletion.)

Showing entries 1-10 | older changes
A322582 a(n) = n - A003958(n), where A003958 is fully multiplicative with a(p) = (p-1).
(history; published version)
#30 by Alois P. Heinz at Sat Feb 18 21:19:19 EST 2023
STATUS

reviewed

approved

#29 by Michael B. Porter at Sat Feb 18 21:02:40 EST 2023
STATUS

proposed

reviewed

#28 by Luc Rousseau at Wed Feb 08 09:12:52 EST 2023
STATUS

editing

proposed

#27 by Luc Rousseau at Wed Feb 08 09:12:12 EST 2023
COMMENTS

With n = Product_{i=1..k} p_i the prime factorization of n, if one forgesconstructs for each i a test with a probability of success equal to 1/p_i, and if the tests are independent, then a(n)/n is the probability that at least one of the k tests succeeds. - Luc Rousseau, Jan 14 2023

STATUS

proposed

editing

Discussion
Wed Feb 08 09:12
Luc Rousseau: Amended
#26 by Jon E. Schoenfield at Sat Jan 14 16:19:50 EST 2023
STATUS

editing

proposed

Discussion
Sat Jan 14 16:21
Luc Rousseau: Thank you
16:34
Jon E. Schoenfield: You're welcome! :-)
Tue Feb 07 21:45
Sean A. Irvine: "forges" -> "constructs" ?  (For me forges suggests something underhand is going on, which is not the case here)
#25 by Jon E. Schoenfield at Sat Jan 14 16:19:37 EST 2023
COMMENTS

With n = ProdProduct_{i=1..k} p_i the prime factorization of n, if one forges for each i a test with a probability of success equal to 1/p_i, and if the tests are independent, then a(n)/n is the probability that at least one of the k tests succeeds. - Luc Rousseau, Jan 14 2023

STATUS

proposed

editing

Discussion
Sat Jan 14 16:19
Jon E. Schoenfield: (correction as required by the OEIS Style Sheet)
#24 by Luc Rousseau at Sat Jan 14 12:23:17 EST 2023
STATUS

editing

proposed

#23 by Luc Rousseau at Sat Jan 14 12:22:51 EST 2023
COMMENTS

With n = Prod_{i=1..k} p_i the prime factorization of n, if one forges for each i a test with a probability of success equal to 1/p_i, and if the tests are independent, then a(n)/n is the probability that at least one of the k tests succeeds. - Luc Rousseau, Jan 14 2023

STATUS

approved

editing

#22 by Susanna Cuyler at Wed Nov 10 18:25:59 EST 2021
STATUS

proposed

approved

#21 by Antti Karttunen at Wed Nov 10 17:16:32 EST 2021
STATUS

editing

proposed

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recents
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy. .

Last modified August 6 10:36 EDT 2024. Contains 374969 sequences. (Running on oeis4.)