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2018 Generali Open Kitzbühel – Doubles

From Wikipedia, the free encyclopedia

Pablo Cuevas and Guillermo Durán were the defending champions, but chose not to participate this year.[1]

Roman Jebavý and Andrés Molteni won the title, defeating Daniele Bracciali and Federico Delbonis in the final, 6–2, 6–4.

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Chile J Peralta
Argentina H Zeballos
6 7
Germany K Krawietz
Chile H Podlipnik-Castillo
3 5 1 Chile J Peralta
Argentina H Zeballos
3 5
Netherlands S Arends
Croatia A Šančić
2 4 Czech Republic R Jebavý
Argentina A Molteni
6 7
Czech Republic R Jebavý
Argentina A Molteni
6 6 Czech Republic R Jebavý
Argentina A Molteni
77 6
4 Germany T Pütz
Germany J-L Struff
6 6 4 Germany T Pütz
Germany J-L Struff
64 3
France H Nys
Belarus A Vasilevski
4 4 4 Germany T Pütz
Germany J-L Struff
7 6
France J Eysseric
Chile N Jarry
6 6 France J Eysseric
Chile N Jarry
5 4
Uruguay A Behar
Spain G García López
3 4 Czech Republic R Jebavý
Argentina A Molteni
6 6
Spain R Carballés Baena
Spain J Munar
6 64 [7] PR Italy D Bracciali
Argentina F Delbonis
2 4
Austria D Novak
Austria D Thiem
4 77 [10] Austria D Novak
Austria D Thiem
WC Austria J Melzer
Germany P Petzschner
77 6 WC Austria J Melzer
Germany P Petzschner
w/o
3 New Zealand M Daniell
Netherlands W Koolhof
64 4 WC Austria J Melzer
Germany P Petzschner
2 0r
WC Austria J Rodionov
Austria T-S Weissborn
5 3 PR Italy D Bracciali
Argentina F Delbonis
6 3
PR Italy D Bracciali
Argentina F Delbonis
7 6 PR Italy D Bracciali
Argentina F Delbonis
7 4 [10]
Ukraine D Molchanov
Slovakia I Zelenay
67 64 2 Belarus M Mirnyi
Austria P Oswald
5 6 [8]
2 Belarus M Mirnyi
Austria P Oswald
79 77

References

  1. ^ "Generali Open Overview". ATP World Tour. Retrieved 28 July 2018.

External links

This page was last edited on 25 May 2022, at 02:34
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